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Many times you hear statements that "moving the tire outwards from the bearing (such as in a reversed or wider rim such as in a wider tire) will cause premature bearing failure." While this statement may be "technically" true, it is realistically untrue. A standard automotive wheel bearing under pristine conditions (flat interstate driving, unloaded, no bumps in the road, etc.) is designed to last 300,000 miles. Under the same conditions, a wider, reversed rim with a larger tire might get 250,000 miles. Point is, there will undoubtedly be other factors that will end the bearing's life before increased loads will, such as lack of maintenance, improper lubrication and contaminants. So, generally speaking, saying that "a larger wheel/tire will wear out a wheel bearing faster" would be similar in saying, "smoking one cigarette will shorten your life." While both statements might be technically true, realistically, they would be immeasurable due to all the other factors that can affect the end result.
Does this mean you can slam on the largest tire you can find and have at 'er without a worry? Hardly. The forces that be are magnified exponentially as you increase the abuse the suspension might see. In order of attrition, those forces include hauling weight, cornering G-forces, Increased Articulation, Rough Terrain, and becoming Airborne. And even through all this, it's not necessarily the Wheel Bearing that will be the weak link, it will usually be the surrounding components, such as the spindle, knuckle, ball joints, axle tube, etc.
In the illustration to the left, the above full reversed offset wheel has a 6 inch offset from the axle connection point to the outside of the tire. The forces at work proved the leverage equivalent to that of a 6 inch lever at the outside of the tire. The diameter of the tire also increases lateral leverages when being subjected to side loads, such as sliding sideways into a curb. There the leverage is equivalent to half of the tire's diameter, which in this case is 15 inches. The tire and rim combination on the lower left illustration depict a tire twice as wide as above example. The outside leverage is equivalent to that of a 12 inch lever at the outside of the tire, almost double that of the top version. HOWEVER, those forces will only be seen when the very outside, and ONLY the outside of the tire is subjected to a force differential. Otherwise, the inside of the tire will begin taking the brunt of the load first, since it has not changed in this illustration. The load will be distributed over more of the tire's width, but not equally, as shown in the example below.
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